Logical Reasoning
hardQ. No. 19728
For an ideal continuously running clock, how many times do the hands coincide between 2 o'clock and 3 o'clock?
Last Updated:
A2time
B0time
C3time
D1time
Correct Answer: 1timeYour Answer: D
Explanation
Correct answer: Option D — 1time. Applying the required separation over a 12-hour cycle gives the verified result 1time. Option A (2time) is rejected because it does not equal the computed result; it represents a counting, direction, leap-year, interval, or hand-motion error. Option B (0time) is rejected because it does not equal the computed result; it represents a counting, direction, leap-year, interval, or hand-motion error. Option C (3time) is rejected because it does not equal the computed result; it represents a counting, direction, leap-year, interval, or hand-motion error.
Important Notes
- Read the complete condition before calculating and write the required reference point, date, or clock time separately. This prevents a correct calculation from answering the reverse question.
- Keep units consistent. Reduce day differences modulo 7; treat 12 on a clock as zero for angle work; and convert gained or lost minutes into the same time unit as the stated interval.
- Check boundary cases explicitly: February, century years, noon, midnight, and an angle greater than 180 degrees often change the apparent answer. A century is a leap year only when divisible by 400.
- Verify the result independently. For calendar problems, move forward or backward by the remainder after division by