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hardQ. No. 5825-a-town-has-population-2614-if-population-grows-by-10-percent-per-year-for-2-years-what-will-be-the

A town has population 2614. If population grows by 10 percent per year for 2 years, what will be the population?

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The percentage expression “A town has population 2614. If population grows by 10 percent per year for 2 years, what will be the population” is evaluated with Future population = present population × (1 + annual rate)^years., producing 3162.94 as the option-specific result.

A3177.94
B3093.94
C3214.94
D3162.94
Correct Answer: 3162.94Your Answer: D

Explanation

Solving “A town has population 2614. If population grows by 10 percent per year for 2 years, what will be the population” requires the relationship Future population = present population × (1 + annual rate)^years.; substituting the stated quantities gives 2614 × 1.1^2 = 3162.94.; hence 3162.94 is the calculated result and option D is correct.

Important Notes

  • Method for “A town has population 2614. If population grows by 10 percent per year for 2 years, what will be the population”: use Future population = present population × (1 + annual rate)^years..
  • Substitution for “A town has population 2614. If population grows by 10 percent per year for 2 years, what will be the population” produces 2614 × 1.1^2 = 3162.94..
  • Calculated answer for “A town has population 2614. If population grows by 10 percent per year for 2 years, what will be the population” is 3162.94, matching option D.
  • Verification for “A town has population 2614. If population grows by 10 percent per year for 2 years, what will be the population”: retain the stated base quantity throughout the percentage calculation.

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Common questions and clear answers for this topic.

A town has population 2614. If population grows by 10% per year for 2 years, what will be the population?

The answer is 3162.94. Using Future population = present population × (1 + annual rate)^years, 2614 × 1.1^2 = 3162.94.

Which formula is used?

Future population = present population × (1 + annual rate)^years

What is Percentage and how is it used in competitive exam problems?

Percentage means per hundred and is used to express a number as a fraction of 100. Formula: Percentage = (Value/Total Value) x 100. In competitive exams like SSC CGL, IBPS Bank PO, and CAT, percentage questions appear as: finding percentage of a number, percentage increase/decrease, percentage change, successive percentage change, and percentage in Data Interpretation.

What are the important percentage-fraction equivalents to memorize?

Important percentage-fraction equivalents: 10% = 1/10, 12.5% = 1/8, 16.67% = 1/6, 20% = 1/5, 25% = 1/4, 33.33% = 1/3, 37.5% = 3/8, 50% = 1/2, 62.5% = 5/8, 66.67% = 2/3, 75% = 3/4. Converting percentages to fractions makes calculations faster. For example: 25% of 480 = 480/4 = 120. Memorizing these fractions is essential for quick Quantitative Aptitude calculations.

How to calculate Percentage Increase and Decrease?

Percentage Increase = (Increase/Original Value) x 100. Percentage Decrease = (Decrease/Original Value) x 100. If price increases by x% then decreases by x%, net effect is a decrease of x squared/100 percent. For Successive Percentage Changes: if first change is a% and second is b%, overall change = a + b + (ab/100) percent. This formula is crucial for profit/loss and interest problems in competitive exams.

How to solve population growth problems using percentage?

Population problems use percentage increase formula. If population is P and annual growth rate is r%, then after n years: Population = P x (1 + r/100)^n. Example: Town population 50,000 grows at 10% per year. After 2 years = 50000 x 1.1 x 1.1 = 60,500. If growth rate decreases, use (1-r/100). These problems appear in SSC CGL, IBPS, and banking exams.

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