Profit and Loss Questions and Answers

The complete calculation confirms 440 as the correct option. For this question, identify every monetary base before applying a percentage. The question-specific working supplied in the record is: This compound interest solved example uses the step-by-step formula A = P(1 + R/100)^n, a reliable shortcut trick for annual compounding. Substituting P = 1000, R = 20, and n = 2 gives A = 1000(1.20)^2 = 1440. Compound interest equals amount minus principal, so CI = 1440 − 1000 = 440. The extra ₹40 arises from interest earned on the first year's ₹200 interest. Therefore, ₹440 is correct, matching option C.. The distractors 460, 400, 420 can result from interchanging cost price and selling price, treating discount as loss, adding successive rates, ignoring quantity, or rounding before the final step. This method preserves the numerical relationships in the stem and develops formula selection, percentage-base recognition and option elimination for SSC, Railway, Banking and other competitive aptitude examinations.

After comparing cost and selling values, the result is 2880. For this question, identify every monetary base before applying a percentage. The question-specific working supplied in the record is: This compound interest solved example uses the step-by-step amount formula A = P(1 + R/100)^n, a fast shortcut trick for annual compounding. Substituting P = 2000, R = 20, and n = 2 gives A = 2000(1.20)^2. Since 1.20 squared equals 1.44, the amount becomes 2000 × 1.44 = ₹2880. This amount includes ₹2000 principal and ₹880 compound interest. Therefore, ₹2880 is correct, matching option B.. The distractors 3000, 3100, 2800 can result from interchanging cost price and selling price, treating discount as loss, adding successive rates, ignoring quantity, or rounding before the final step. This method preserves the numerical relationships in the stem and develops formula selection, percentage-base recognition and option elimination for SSC, Railway, Banking and other competitive aptitude examinations.

Correct percentage analysis gives 1324, corresponding to option B. For this question, identify every monetary base before applying a percentage. The question-specific working supplied in the record is: This compound interest solved example uses the step-by-step formula A = P(1 + R/100)^n, the fastest shortcut trick for annual compounding. Substituting P = 4000, R = 10, and n = 3 gives A = 4000(1.10)^3 = 4000 × 1.331 = 5324. Compound interest equals amount minus principal, so CI = 5324 − 4000 = 1324. The third year's interest is also calculated on the accumulated amount. Therefore, ₹1324 is correct, matching option C.. The distractors 1240, 1400, 1200 can result from interchanging cost price and selling price, treating discount as loss, adding successive rates, ignoring quantity, or rounding before the final step. This method preserves the numerical relationships in the stem and develops formula selection, percentage-base recognition and option elimination for SSC, Railway, Banking and other competitive aptitude examinations.

The verified answer is 1452, option B. For this question, identify every monetary base before applying a percentage. The question-specific working supplied in the record is: This compound interest solved example uses the step-by-step amount formula A = P(1 + R/100)^n, a quick shortcut trick for annual compounding. Substituting P = 1200, R = 10, and n = 2 gives A = 1200(1.10)^2. Since 1.10 squared equals 1.21, the amount becomes 1200 × 1.21 = ₹1452. This amount includes ₹1200 principal and ₹252 compound interest. Therefore, ₹1452 is correct, matching option B.. The distractors 1400, 1500, 1550 can result from interchanging cost price and selling price, treating discount as loss, adding successive rates, ignoring quantity, or rounding before the final step. This method preserves the numerical relationships in the stem and develops formula selection, percentage-base recognition and option elimination for SSC, Railway, Banking and other competitive aptitude examinations.

The complete calculation confirms 636 as the correct option. For this question, identify every monetary base before applying a percentage. The question-specific working supplied in the record is: This compound interest solved example uses the step-by-step formula A = P(1 + R/100)^n, a reliable shortcut trick for annual compounding. Substituting P = 2500, R = 12, and n = 2 gives A = 2500(1.12)^2 = 3136. Compound interest is obtained by subtracting the principal from the amount, so CI = 3136 − 2500 = ₹636. Simply doubling 12% would ignore the interest earned on the first year's interest during the second year. Thus, the mathematically correct answer is ₹636, corresponding to option B.. The distractors 670, 600, 650 can result from interchanging cost price and selling price, treating discount as loss, adding successive rates, ignoring quantity, or rounding before the final step. This method preserves the numerical relationships in the stem and develops formula selection, percentage-base recognition and option elimination for SSC, Railway, Banking and other competitive aptitude examinations.

After comparing cost and selling values, the result is 6050. For this question, identify every monetary base before applying a percentage. The question-specific working supplied in the record is: This compound interest solved example uses the step-by-step amount formula A = P(1 + R/100)^n, which is the fastest shortcut trick for annual compounding. Substituting P = 5000, R = 10, and n = 2 gives A = 5000(1.10)^2. Since 1.10 squared is 1.21, the final amount is 5000 × 1.21 = ₹6050. The amount includes both the original principal and accumulated compound interest. Therefore, ₹6050 is correct, matching option B.. The distractors 6100, 6150, 6000 can result from interchanging cost price and selling price, treating discount as loss, adding successive rates, ignoring quantity, or rounding before the final step. This method preserves the numerical relationships in the stem and develops formula selection, percentage-base recognition and option elimination for SSC, Railway, Banking and other competitive aptitude examinations.

For this question, identify every monetary base before applying a percentage. The question-specific working supplied in the record is: This compound interest solved example uses the step-by-step formula A = P(1 + R/100)^n, a dependable shortcut trick for annual compounding. Substituting P = 3000, R = 10, and n = 2 gives A = 3000(1.10)^2 = 3630. Compound interest equals amount minus principal, so CI = 3630 − 3000 = 630. The extra ₹30 arises because the second year earns interest on the first year's interest. Therefore, ₹630 is correct, matching option B.. The distractors 660, 690, 600 can result from interchanging cost price and selling price, treating discount as loss, adding successive rates, ignoring quantity, or rounding before the final step. This method preserves the numerical relationships in the stem and develops formula selection, percentage-base recognition and option elimination for SSC, Railway, Banking and other competitive aptitude examinations.

The verified answer is 120, option C. For this question, identify every monetary base before applying a percentage. The question-specific working supplied in the record is: This compound interest solved example uses the one-year shortcut trick: compound interest and simple interest are identical for the first year. The step-by-step formula gives CI = P × R/100 = 1500 × 8/100. Multiplying and dividing yields ₹120. No interest-on-interest component arises because only one annual period is involved. Therefore, ₹120 is correct, matching option C.. The distractors 100, 110, 130 can result from interchanging cost price and selling price, treating discount as loss, adding successive rates, ignoring quantity, or rounding before the final step. A dependable check is to assume cost price 100 whenever only percentages are involved, reconstruct the selling value, and compare the resulting ratio with the selected option. This method preserves the numerical relationships in the stem and develops formula selection, percentage-base recognition and option elimination for SSC, Railway, Banking and other competitive aptitude examinations.

The complete calculation confirms 2205 as the correct option. For this question, identify every monetary base before applying a percentage. The question-specific working supplied in the record is: This compound interest solved example applies the step-by-step amount formula A = P(1 + R/100)^n, the standard shortcut trick for yearly compounding. Substituting P = 2000, R = 5, and n = 2 gives A = 2000(1.05)^2. Since 1.05 squared equals 1.1025, the amount is 2000 × 1.1025 = ₹2205. This amount includes the original principal and ₹205 compound interest. Therefore, ₹2205 is correct, matching option B.. The distractors 2400, 2100, 2300 can result from interchanging cost price and selling price, treating discount as loss, adding successive rates, ignoring quantity, or rounding before the final step. This method preserves the numerical relationships in the stem and develops formula selection, percentage-base recognition and option elimination for SSC, Railway, Banking and other competitive aptitude examinations.

After comparing cost and selling values, the result is 210. For this question, identify every monetary base before applying a percentage. The question-specific working supplied in the record is: This compound interest solved example uses the step-by-step formula A = P(1 + R/100)^n, a reliable shortcut trick for annual compounding. Substituting P = 1000, R = 10, and n = 2 gives A = 1000(1.10)^2 = 1210. Compound interest is the amount minus the principal, so CI = 1210 − 1000 = 210. The second year's interest includes interest on the first year's ₹100 interest. Therefore, ₹210 is correct, matching option B.. The distractors 220, 230, 200 can result from interchanging cost price and selling price, treating discount as loss, adding successive rates, ignoring quantity, or rounding before the final step. This method preserves the numerical relationships in the stem and develops formula selection, percentage-base recognition and option elimination for SSC, Railway, Banking and other competitive aptitude examinations.