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easyQ. No. 16838-solve-this-time-and-work-question-arjun-can-build-a-boundary-wall-alone-in-9-hours-and-danish-can

Solve this Time and Work question: Arjun can build a boundary wall alone in 9 hours and Danish can build the same wall alone in 10 hours. When they work together, coordination delays reduce their combined output by 10 bricks per hour. Even then, they finish the wall in 5 hours. How many bricks are used in the wall?

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This bilingual Time and Work item asks the learner to solve “Solve this Time and Work question: Arjun can build a boundary wall alone in 9 hours and Danish can build the same wall alone in 10 hours. When they work together, coordination delays reduce their combined output by 10 bricks per hour. Even then, they finish the wall in 5 hours. How many bricks are used in the wall?” through a complete, auditable work-rate equation. The validated answer is 900 bricks.

A720 bricks
B810 bricks
C900 bricks
D990 bricks
Correct Answer: 900 bricksYour Answer: C

Explanation

The verified answer to “Solve this Time and Work question: Arjun can build a boundary wall alone in 9 hours and Danish can build the same wall alone in 10 hours. When they work together, coordination delays reduce their combined output by 10 bricks per hour. Even then, they finish the wall in 5 hours. How many bricks are used in the wall?” is 900 bricks, option C. The question-specific working supplied with the item states: Let the wall contain N bricks. Arjun's hourly output = N/9 and Danish's hourly output = N/10. Their theoretical combined output is N/9 + N/10 = 19N/90 bricks per hour. They complete the wall in 5 hours, so actual output is N/5 = 18N/90. This gives N/90 = 10 and hence N = 900 bricks. This working identifies the relevant work-rate equation and connects the given information to the required result. After applying the verified rule, the required value or position is 900 bricks. The alternatives 720 bricks, 810 bricks and 990 bricks fail because each breaks at least one stated condition, transition, direction or arithmetic step. A plausible-looking option is not sufficient unless it reproduces the complete work-rate equation. This full replay leads only to 900 bricks, so option C is uniquely correct.

Important Notes

  • Rebuild the complete Time and Work work-rate equation before selecting 900 bricks.
  • Question-specific Time and Work working connects the stated clues or terms directly with 900 bricks.
  • Options 720 bricks, 810 bricks, 990 bricks each break a condition or transition in this Time and Work item.
  • Replay every step in the Time and Work work-rate equation to independently confirm 900 bricks.

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Common questions and clear answers for this topic.

What is the verified answer to “Solve this Time and Work question: Arjun can build a boundary wall alone in 9 hours and Danish can build the same wall alone in 10 hours. When they work together, coordination delays reduce their combined output by 10 bricks per hour. Even then, they finish the wall in 5 hours. How many bricks are used in the wall?”?

900 bricks, option C.

Which method solves this Time and Work item?

Rebuild and verify the complete work-rate equation.

Why are the other options incorrect?

720 bricks, 810 bricks, 990 bricks break a clue, direction, transition or operation.

How should the answer be checked?

Replay the rule from the first clue or term and test every intermediate step.

What is Time and Work and what is the basic concept?

Time and Work problems involve finding how long it takes to complete a task. Basic concept: If A can do a work in n days, A's one day work = 1/n. If A and B together can do work in n days, combined one day work = 1/n. Key formula: Total Work = Efficiency x Time. Time and Work is a major topic in SSC CGL, IBPS Bank PO, SBI PO, CAT, and Railway exams.

How to solve Time and Work problems using LCM method?

LCM Method: Assume total work = LCM of given days. Calculate each person's work per day = Total work divided by Days. Combined work per day = Sum of individual work rates. Time = Total work divided by Combined rate. Example: A can do work in 10 days, B in 15 days. LCM(10,15) = 30 units. A's daily work = 3 units, B's = 2 units. Together = 5 units/day. Time = 30/5 = 6 days. This avoids fractions and is much faster.