Direction Test Questions and Answers – Page 4

Use coordinates with O = (0, 0), East as positive x and North as positive y. Horizontal calculation: the person moves 5 m East and 5 m West, so net x = 5 - 5 = 0 m. Vertical calculation: the person moves 10 m North and 5 m South, so net y = 10 - 5 = 5 m. The signs of (0, 5) place the final point in the North direction. The shortest distance is straight-line displacement: √((0)² + (5)²) = √(0 + 25) = √25 = 5 m. Therefore option D, North, 5 m, is correct. The opposite-direction option is wrong because it reverses the verified coordinate signs. The option giving 7 m is wrong because it does not use the Pythagorean shortest distance. The North-East option is wrong because both non-zero coordinate components, or the exact zero component, determine North, not a neighbouring compass direction.

Use coordinates with O = (0, 0), East as positive x and North as positive y. Horizontal calculation: the person moves 4 m East and 4 m West, so net x = 4 - 4 = 0 m. Vertical calculation: the person moves 9 m North and 4 m South, so net y = 9 - 4 = 5 m. The signs of (0, 5) place the final point in the North direction. The shortest distance is straight-line displacement: √((0)² + (5)²) = √(0 + 25) = √25 = 5 m. Therefore option C, North, 5 m, is correct. The opposite-direction option is wrong because it reverses the verified coordinate signs. The option giving 7 m is wrong because it does not use the Pythagorean shortest distance. The North-East option is wrong because both non-zero coordinate components, or the exact zero component, determine North, not a neighbouring compass direction.

Use coordinates with O = (0, 0), East as positive x and North as positive y. Horizontal calculation: the person moves 9 m East and 4 m West, so net x = 9 - 4 = 5 m. Vertical calculation: the person moves 4 m North and 4 m South, so net y = 4 - 4 = 0 m. The signs of (5, 0) place the final point in the East direction. The shortest distance is straight-line displacement: √((5)² + (0)²) = √(25 + 0) = √25 = 5 m. Therefore option B, East, 5 m, is correct. The opposite-direction option is wrong because it reverses the verified coordinate signs. The option giving 7 m is wrong because it does not use the Pythagorean shortest distance. The South-East option is wrong because both non-zero coordinate components, or the exact zero component, determine East, not a neighbouring compass direction.

Use coordinates with O = (0, 0), East as positive x and North as positive y. Horizontal calculation: the person moves 8 m East and 3 m West, so net x = 8 - 3 = 5 m. Vertical calculation: the person moves 3 m North and 3 m South, so net y = 3 - 3 = 0 m. The signs of (5, 0) place the final point in the East direction. The shortest distance is straight-line displacement: √((5)² + (0)²) = √(25 + 0) = √25 = 5 m. Therefore option A, East, 5 m, is correct. The opposite-direction option is wrong because it reverses the verified coordinate signs. The option giving 7 m is wrong because it does not use the Pythagorean shortest distance. The South-East option is wrong because both non-zero coordinate components, or the exact zero component, determine East, not a neighbouring compass direction.

Use coordinates with O = (0, 0), East as positive x and North as positive y. Horizontal calculation: the person moves 7 m East and 11 m West, so net x = 7 - 11 = -4 m. Vertical calculation: the person moves 7 m North and 10 m South, so net y = 7 - 10 = -3 m. The signs of (-4, -3) place the final point in the South-West direction. The shortest distance is straight-line displacement: √((-4)² + (-3)²) = √(16 + 9) = √25 = 5 m. Therefore option D, South-West, 5 m, is correct. The opposite-direction option is wrong because it reverses the verified coordinate signs. The option giving 7 m is wrong because it does not use the Pythagorean shortest distance. The West option is wrong because both non-zero coordinate components, or the exact zero component, determine South-West, not a neighbouring compass direction.

Use coordinates with O = (0, 0), East as positive x and North as positive y. Horizontal calculation: the person moves 6 m East and 10 m West, so net x = 6 - 10 = -4 m. Vertical calculation: the person moves 6 m North and 9 m South, so net y = 6 - 9 = -3 m. The signs of (-4, -3) place the final point in the South-West direction. The shortest distance is straight-line displacement: √((-4)² + (-3)²) = √(16 + 9) = √25 = 5 m. Therefore option C, South-West, 5 m, is correct. The opposite-direction option is wrong because it reverses the verified coordinate signs. The option giving 7 m is wrong because it does not use the Pythagorean shortest distance. The West option is wrong because both non-zero coordinate components, or the exact zero component, determine South-West, not a neighbouring compass direction.

Use coordinates with O = (0, 0), East as positive x and North as positive y. Horizontal calculation: the person moves 6 m East and 9 m West, so net x = 6 - 9 = -3 m. Vertical calculation: the person moves 6 m North and 10 m South, so net y = 6 - 10 = -4 m. The signs of (-3, -4) place the final point in the South-West direction. The shortest distance is straight-line displacement: √((-3)² + (-4)²) = √(9 + 16) = √25 = 5 m. Therefore option B, South-West, 5 m, is correct. The opposite-direction option is wrong because it reverses the verified coordinate signs. The option giving 7 m is wrong because it does not use the Pythagorean shortest distance. The West option is wrong because both non-zero coordinate components, or the exact zero component, determine South-West, not a neighbouring compass direction.

Use coordinates with O = (0, 0), East as positive x and North as positive y. Horizontal calculation: the person moves 5 m East and 8 m West, so net x = 5 - 8 = -3 m. Vertical calculation: the person moves 5 m North and 9 m South, so net y = 5 - 9 = -4 m. The signs of (-3, -4) place the final point in the South-West direction. The shortest distance is straight-line displacement: √((-3)² + (-4)²) = √(9 + 16) = √25 = 5 m. Therefore option A, South-West, 5 m, is correct. The opposite-direction option is wrong because it reverses the verified coordinate signs. The option giving 7 m is wrong because it does not use the Pythagorean shortest distance. The West option is wrong because both non-zero coordinate components, or the exact zero component, determine South-West, not a neighbouring compass direction.

Use coordinates with O = (0, 0), East as positive x and North as positive y. Horizontal calculation: the person moves 9 m East and 5 m West, so net x = 9 - 5 = 4 m. Vertical calculation: the person moves 5 m North and 8 m South, so net y = 5 - 8 = -3 m. The signs of (4, -3) place the final point in the South-East direction. The shortest distance is straight-line displacement: √((4)² + (-3)²) = √(16 + 9) = √25 = 5 m. Therefore option D, South-East, 5 m, is correct. The opposite-direction option is wrong because it reverses the verified coordinate signs. The option giving 7 m is wrong because it does not use the Pythagorean shortest distance. The South option is wrong because both non-zero coordinate components, or the exact zero component, determine South-East, not a neighbouring compass direction.

Use coordinates with O = (0, 0), East as positive x and North as positive y. Horizontal calculation: the person moves 8 m East and 4 m West, so net x = 8 - 4 = 4 m. Vertical calculation: the person moves 4 m North and 7 m South, so net y = 4 - 7 = -3 m. The signs of (4, -3) place the final point in the South-East direction. The shortest distance is straight-line displacement: √((4)² + (-3)²) = √(16 + 9) = √25 = 5 m. Therefore option C, South-East, 5 m, is correct. The opposite-direction option is wrong because it reverses the verified coordinate signs. The option giving 7 m is wrong because it does not use the Pythagorean shortest distance. The South option is wrong because both non-zero coordinate components, or the exact zero component, determine South-East, not a neighbouring compass direction.