Percentage Questions and Answers – Page 87
Percentage is one of the most fundamental and frequently tested topics in Quantitative Aptitude for competitive exams such as SSC CGL, SSC CHSL, IBPS PO, IBPS Clerk, SBI PO, SBI Clerk, RRB NTPC and other banking and government job examinations. At its core, percentage represents a number expressed as a fraction of 100, calculated using the formula Percentage = (Value/Total Value) x 100. Mastering percentage calculations is essential because this topic forms the foundation for several other important Quantitative Aptitude chapters, including Profit and Loss, Simple Interest, Compound Interest, Ratio and Proportion, and Data Interpretation. Students preparing for banking and SSC exams regularly encounter percentage-based questions in the form of percentage increase and decrease, percentage change, successive percentage change, population growth and depreciation problems, and percentage-to-fraction conversions. This topic page offers a comprehensive collection of percentage questions with detailed, step-by-step solutions designed to help aspirants build speed and accuracy for competitive exams. Our percentage practice set covers all important question types asked in SSC CGL, SSC CHSL, IBPS, SBI, RRB NTPC, RRB Group D, and other government exams, ranging from basic percentage calculation to advanced successive percentage change and data interpretation based percentage problems. Each question comes with a clear explanation, shortcut tricks, and time-saving formulas that make it easier to solve percentage problems within seconds during the exam. Aspirants preparing for banking and SSC exams often find percentage questions tricky due to time constraints. To overcome this challenge, our practice questions include percentage-fraction equivalents, quick calculation shortcuts, and important formulas for percentage increase, percentage decrease, and successive percentage change. Regular practice of these percentage questions will strengthen your Quantitative Aptitude preparation and help you score better in the quantitative aptitude section of any competitive exam. Whether you are a beginner just starting your preparation or an experienced aspirant looking to sharpen your speed and accuracy, this percentage question bank is designed to cater to all skill levels. Practice daily, analyze your mistakes, and use the shortcut methods provided here to solve percentage-based questions faster and more accurately in your upcoming SSC, banking, railway, and other competitive government exams.
FAQ
Percentage FAQs
Common questions and clear answers for this topic.
What is Percentage and how is it used in competitive exam problems?
Percentage means per hundred and is used to express a number as a fraction of 100. Formula: Percentage = (Value/Total Value) x 100. In competitive exams like SSC CGL, IBPS Bank PO, and CAT, percentage questions appear as: finding percentage of a number, percentage increase/decrease, percentage change, successive percentage change, and percentage in Data Interpretation.
What are the important percentage-fraction equivalents to memorize?
Important percentage-fraction equivalents: 10% = 1/10, 12.5% = 1/8, 16.67% = 1/6, 20% = 1/5, 25% = 1/4, 33.33% = 1/3, 37.5% = 3/8, 50% = 1/2, 62.5% = 5/8, 66.67% = 2/3, 75% = 3/4. Converting percentages to fractions makes calculations faster. For example: 25% of 480 = 480/4 = 120. Memorizing these fractions is essential for quick Quantitative Aptitude calculations.
How to calculate Percentage Increase and Decrease?
Percentage Increase = (Increase/Original Value) x 100. Percentage Decrease = (Decrease/Original Value) x 100. If price increases by x% then decreases by x%, net effect is a decrease of x squared/100 percent. For Successive Percentage Changes: if first change is a% and second is b%, overall change = a + b + (ab/100) percent. This formula is crucial for profit/loss and interest problems in competitive exams.
How to solve population growth problems using percentage?
Population problems use percentage increase formula. If population is P and annual growth rate is r%, then after n years: Population = P x (1 + r/100)^n. Example: Town population 50,000 grows at 10% per year. After 2 years = 50000 x 1.1 x 1.1 = 60,500. If growth rate decreases, use (1-r/100). These problems appear in SSC CGL, IBPS, and banking exams.
What is the shortcut method to find percentage of numbers quickly?
Shortcut methods: 1) For 1%: divide by 100, 2) For 10%: divide by 10, 3) For 5%: divide by 20 (half of 10%), 4) For 15%: find 10% then add half, 5) For 20%: divide by 5, 6) For 25%: divide by 4, 7) For 50%: divide by 2, 8) For 75%: multiply by 3 and divide by 4. Combine these for complex percentages: 35% = 30% + 5% = (3 x 10%) + (5%). Practice mental math with these shortcuts for exam speed.
After an increase of 15%, a number becomes 650. What was the original number?
The answer is 565.22. Using Original value = final value ÷ (1 + rate), 650 ÷ 1.15 = 565.22.
Which formula is used?
Original value = final value ÷ (1 + rate)
After an increase of 18%, a number becomes 287. What was the original number?
The answer is 243.22. Using Original value = final value ÷ (1 + rate), 287 ÷ 1.18 = 243.22.
A town has population 6560. If population grows by 5% per year for 3 years, what will be the population?
The answer is 7594.02. Using Future population = present population × (1 + annual rate)^years, 6560 × 1.05^3 = 7594.02.
A town has population 4332. If population grows by 5% per year for 2 years, what will be the population?
The answer is 4776.03. Using Future population = present population × (1 + annual rate)^years, 4332 × 1.05^2 = 4776.03.
A town has population 6028. If population grows by 10% per year for 2 years, what will be the population?
The answer is 7293.88. Using Future population = present population × (1 + annual rate)^years, 6028 × 1.1^2 = 7293.88.
The price of an item is ₹225. If it increases by 15%, what is the new price?
The answer is 258.75. Using New value = original value × (1 + increase rate), 225 × 1.15 = 258.75.
The price of an item is ₹447. If it increases by 10%, what is the new price?
The answer is 491.7. Using New value = original value × (1 + increase rate), 447 × 1.1 = 491.7.
A town has population 2252. If population grows by 12% per year for 2 years, what will be the population?
The answer is 2824.91. Using Future population = present population × (1 + annual rate)^years, 2252 × 1.12^2 = 2824.91.
A town has population 6683. If population grows by 10% per year for 3 years, what will be the population?
The answer is 8895.07. Using Future population = present population × (1 + annual rate)^years, 6683 × 1.1^3 = 8895.07.
The price of an item is ₹372. If it increases by 20%, what is the new price?
The answer is 446.4. Using New value = original value × (1 + increase rate), 372 × 1.2 = 446.4.
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